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returning a dictionary I am trying to take a dictionary and convert it to scala Future using Future.valueAs[String, String], so that I can query



 

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macdrive 8 pro crack free download for windows mac drive 8 pro free download mac drive 8 References Category:1998 softwareQ: scala Future returning a dictionary I am trying to take a dictionary and convert it to scala Future using Future.valueAs[String, String], so that I can query the API later. I am trying to use Future.valueAs[String, String] because I need to translate a query from a dict to a query. This is the implementation of the method I am trying to convert: def valueAs[V](v: T)(f: V => T): Future[T] = { scala.concurrent.Future { try { //assume ret is a result type of Future. ret } catch { case e: Throwable => throw new Exception("Unable to convert " + v + " to " + ret) } } } This is the code that is called by the method in question: val d = Http().get("") val u = d.map { case (username, url) => (username, url) } val request = for { username T)is not a member of scala.util.Try Any idea how to fix this? A: You've got two things going wrong. First, you're not mapping over the Future in the first place. You need something like: val futureDictionary = request.map(r => r.map(...).map(...)...).map(...) The other issue, though, is that you're trying to map over the Future, which won't work




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